Issue

While I was solving this, I came across the need to somehow solve this in linear time. The question requires sorting the map’s value, which stores the frequency of that integer.

This reference explanation explained really well.

Without bucket sort (using PQ)

class Solution {
    public int[] topKFrequent(int[] nums, int k) {
        Map<Integer, Integer> map = new HashMap<>();
        
        for(int i : nums){
            map.put(i, map.getOrDefault(i, 0) + 1);
        }
        
        PriorityQueue<Integer> maxHeap = new PriorityQueue<>((a,b) -> map.get(b) - map.get(a));
        
        for(int key : map.keySet()){
            maxHeap.add(key);
        }
        
        int res[] = new int[k];
        for(int i = 0; i < k; i++){
            res[i] = maxHeap.poll();
        }
        return res;
    }
}

This is O(n log n) time, we can do linear time with bucket sort.

Bucket sort

Again, look at the reference explanation.